Sure! Here are the answers to the questions based on the information provided:
Question 1
Perry's sequence formula regarding the number of carrots is:
- Coefficient of the sequence formula is 20.
- Exponential factor of the sequence formula is (1/2)^(n-1).
Question 2
The equation \( y=4,060(1−0.05)^t \) represents the decay of a specific species of bird. The rate of decay is:
- Option #3: The rate of decay is 5%.
Question 3
To create an exponential decay function for the antelope population, we use the formula:
\[ P(t) = P_0 (1 - r)^t \]
Where:
- \( P_0 = 570 \) (initial population)
- \( r = 0.06 \) (rate of decline)
- \( t = 10 \) (years)
So the function becomes:
\[ P(t) = 570 (1 - 0.06)^{10} = 570 (0.94)^{10} \]
Calculating this gives:
\[ P(10) \approx 570 \times 0.537 \approx 306.09 \]
Rounding to the nearest whole number, there will be 306 antelopes after 10 years.
Question 4
Based on the graph modeled by the points and the equation \( y = 3(0.75)^x \), the horizontal asymptote can be derived. The horizontal asymptote approaches \( y = 0 \) as \( x \) increases, but considering the graph's behavior at lower values:
- The horizontal asymptote is at y = 0.
Question 5
For the function \( y = 30(0.85)^x \), to find the y-intercept, we set \( x = 0 \):
\[ y = 30(0.85)^0 = 30(1) = 30 \]
So the y-intercept is at the point (0, 30).
In summary:
- After 10 years, there will be 306 antelopes.
- The horizontal asymptote is at y = 0.
- The y-intercept is at the point (0, 30).