momentum is conserved. In this case, we are considering only the horizontal motion, since the wagon cannot move vertically.
So, the basic problem is that of what happens when the wagon's mass is suddenly increased by the addition of the bird's mass.
To conserve momentum, the new larger mass has to slow down. Momentum is mass * velocity, so
11*4 = (11+4.2)v
Now just solve for v.
Question 1:A child's wagon with a mass of 11 kg is moving at a constant speed of 4 m/s on a horizontal frictionless surface at the Houston Zoo. After a 4.2 kg Southern Ground Hornbill lands by vertical descent in the child's wagon, the velocity of the wagon will be Answer m/s.
Question 2: A child's wagon with a mass of 19 kg is moving at a constant speed of 2 m/s on a horizontal frictionless surface at the Houston Zoo. When a 4.2 kg Southern Ground Hornbill lands by vertical descent in the child's wagon, the momentum of the wagon and the hornbill will be AnswerIncorrect kg m/s.
~ I know these are the same type of questions.... I just don't understand momentum...~
1 answer
1 answer