Question 1 (1 point)

Question

Saved
In Mendel's experiments with pea plant, if a true-breeding yellow pea plant (YY) is crossed with a true-breeding green pea plant (yy), what will be the genotype(s) of the F1 generation?

Question 1 options:

YY

Yy

yy

YY and yy

Question 2 (1 point)
In a dihybrid cross between two individuals heterozygous for both traits (RrYy x RrYy), what is the phenotypic ratio of the offspring according to Mendel's principles?

Question 2 options:

1:1

3:1

9:3:3:1

9:7

Question 3 (1 point)
In a test cross, an individual with a dominant phenotype but unknown genotype is crossed with a homozygous recessive individual. What is the purpose of this cross?

Question 3 options:

To determine the phenotype of the dominant individual.

To produce offspring with the same phenotype as the dominant individual.

To determine the phenotype of the offspring.

To determine if the dominant individual is heterozygous or homozygous dominant.

Question 4 (1 point)
In humans, freckles (F) are dominant over no freckles (f). If two individuals heterozygous for freckles (Ff) have children, what is the probability that they will have a child without freckles?

Question 4 options:

0%

25%

50%

75%

Question 5 (1 point)
In a monohybrid cross between a heterozygous individual (Aa) and a homozygous dominant individual (AA), what is the probability of obtaining offspring with the homozygous recessive genotype (aa)?

Question 5 options:

100%

75%

50%

0%

Question 6 (1 point)
If a genetic disorder is caused by a recessive allele, what is the probability that two carrier parents (Aa) will have an affected child?

Question 6 options:

0%

25%

50%

75%

Question 7 (1 point)
In a cross between a plant with red flowers (RR) and a plant with white flowers (rr), if all of the offspring have pink flowers (Rr), what type of inheritance pattern is exhibited?

Question 7 options:

Incomplete dominance

Codominance

Autosomal dominant

Sex-linked dominant

Question 8 (1 point)
In a cross between a homozygous dominant individual and a homozygous recessive individual, what will be the genotype(s) of the F1 generation?

Question 8 options:

All heterozygous

All homozygous dominant

All homozygous recessive

All heterozygous and homozygous dominant

Question 9 (1 point)
Which of the following accurately describes a codominance cross?

Question 9 options:

One allele is completely dominant over the other, leading to a clear dominant phenotype.

Both alleles contribute equally to the phenotype, resulting in a heterozygous individual showing a mixture of both traits.

One allele is recessive to the other, causing the dominant allele to mask its expression.

The alleles are located on different chromosomes, resulting in independent assortment.

Question 10 (1 point)
Saved
Recall that females have two X chromosomes: one from the mother and one from the father. Males have one X chromosome and one Y chromosome; the X chromosome comes from the mother, and the Y chromosome comes from the father. Traits associated with genes located on the sex chromosomes are called sex-linked traits.

Individuals with the sex-linked condition called red-green color blindness do not perceive the colors red and green. Red-green color blindness is caused by the recessive allele b and is carried on the X chromosome. The dominant allele for normal color vision is B. When an X chromosome contains the dominant allele, the allele is written as XB. When an X chromosome contains the recessive allele, the allele is written as Xb.

A man who is color-blind marries a woman who is not color-blind and is not a carrier of the allele for colorblindness. Create a Punnett square to predict the possible genotypes of their children. What is the probability that a son of this couple will be color-blind?

Question 10 options:

100%

75%

50%

0%

Answer 1

Here are the answers to your questions:

Question 1: In Mendel's experiments with pea plants, if a true-breeding yellow pea plant (YY) is crossed with a true-breeding green pea plant (yy), what will be the genotype(s) of the F1 generation?

• Answer: Yy

Question 2: In a dihybrid cross between two individuals heterozygous for both traits (RrYy x RrYy), what is the phenotypic ratio of the offspring according to Mendel's principles?

• Answer: 9:3:3:1

Question 3: In a test cross, an individual with a dominant phenotype but unknown genotype is crossed with a homozygous recessive individual. What is the purpose of this cross?

• Answer: To determine if the dominant individual is heterozygous or homozygous dominant.

Question 4: In humans, freckles (F) are dominant over no freckles (f). If two individuals heterozygous for freckles (Ff) have children, what is the probability that they will have a child without freckles?

• Answer: 25%

Question 5: In a monohybrid cross between a heterozygous individual (Aa) and a homozygous dominant individual (AA), what is the probability of obtaining offspring with the homozygous recessive genotype (aa)?

• Answer: 0%

Question 6: If a genetic disorder is caused by a recessive allele, what is the probability that two carrier parents (Aa) will have an affected child?

• Answer: 25%

Question 7: In a cross between a plant with red flowers (RR) and a plant with white flowers (rr), if all of the offspring have pink flowers (Rr), what type of inheritance pattern is exhibited?

• Answer: Incomplete dominance

Question 8: In a cross between a homozygous dominant individual and a homozygous recessive individual, what will be the genotype(s) of the F1 generation?

• Answer: All heterozygous

Question 9: Which of the following accurately describes a codominance cross?

• Answer: Both alleles contribute equally to the phenotype, resulting in a heterozygous individual showing a mixture of both traits.

Question 10: A man who is color-blind marries a woman who is not color-blind and is not a carrier of the allele for colorblindness. What is the probability that a son of this couple will be color-blind?

• The man is XbY (color-blind), and the woman is XBXB (not color-blind, not a carrier). The Punnett square will show the following genotypes for their sons:
• XB Y (normal vision)
• XB Y (normal vision)

So, the probability that a son of this couple will be color-blind is:

• Answer: 0%

Overall, here are the answers compiled:

1. Yy
2. 9:3:3:1
3. To determine if the dominant individual is heterozygous or homozygous dominant.
4. 25%
5. 0%
6. 25%
7. Incomplete dominance
8. All heterozygous
9. Both alleles contribute equally to the phenotype, resulting in a heterozygous individual showing a mixture of both traits.
10. 0%