Let's break down each question step by step:
Question 1:
To find the inequality for comparing the costs of Company X and Company Y:
Company X: Cost = $50 + $7x (where x is the number of caps)
Company Y: Cost = $30 + $9x
To find when Company X is cheaper than Company Y: \[ 50 + 7x < 30 + 9x \] Rearranging gives: \[ 50 - 30 < 9x - 7x \] \[ 20 < 2x \] or \[ 10 < x \] So, the inequality is: x > 10
Question 2:
Jamal has $15.00. He spends $7.50 on nachos and wants to buy boxes of candy that cost $1.75 each.
Remaining money after buying nachos: \[ 15.00 - 7.50 = 7.50 \] Let y be the number of boxes of candy. The inequality is: \[ 1.75y \leq 7.50 \]
Question 3:
Greg needs $550 for a new cell phone, he currently has $300, and he wants to buy it in 4 weeks:
Amount needed to save: \[ 550 - 300 = 250 \] If x is the amount he needs to save each week: \[ 4x \geq 250 \] So the inequality is: x ≥ 62.5
Question 4:
We found that Company X is cheaper when: x > 10 caps.
Question 5:
Using the remaining money after buying nachos: He can spend $7.50 on candy, and each box of candy costs $1.75:
Calculating maximum boxes of candy: \[ 7.50 ÷ 1.75 ≈ 4.29 \] Thus, he can buy: 4 or fewer boxes of candy.
Summary of Answers:
- For Company X to be cheaper: x > 10
- Jamal's inequality for boxes of candy: 1.75y ≤ 7.50
- Greg's inequality for saving: x ≥ 62.5
- For number of caps where Company X is cheaper: More than 10 caps
- Number of boxes of candy Jamal can purchase: 4 or fewer boxes of candy