Quadrilateral QRST has vertices at Q(−1,5), R(2,8), S(4,4), and T(1,1). The measure of Angle Q is 108° and the measure of angle R is (108−2x)°.



Determine if quadrilateral QRST is a parallelogram, and if so, solve for x.​

(1 point)
Responses

Quadrilateral QRST is a parallelogram because there are four sides. The value x = 108 because the angles are congruent.
Quadrilateral QRST is a parallelogram because there are four sides. The value x = 108 because the angles are congruent.

Quadrilateral QRST is a parallelogram because there are two pairs of parallel lines. The value x = 0 because the angles are congruent.
Quadrilateral QRST is a parallelogram because there are two pairs of parallel lines. The value x = 0 because the angles are congruent.

Quadrilateral QRST is a parallelogram because there are two pairs of parallel lines. The value x = 18 because the angles are supplementary.
Quadrilateral QRST is a parallelogram because there are two pairs of parallel lines. The value x = 18 because the angles are supplementary.

Quadrilateral QRST is NOT a parallelogram because there are NOT two pairs of parallel lines.

1 answer

To determine whether quadrilateral QRST is a parallelogram and to find the value of \( x \), we will first consider the properties of angles in a quadrilateral.

In any quadrilateral, the sum of the interior angles is \( 360^\circ \). We know that:

  • \( \angle Q = 108^\circ \)
  • \( \angle R = (108 - 2x)^\circ \)

Let’s denote the measures of angles \( S \) and \( T \) as \( \angle S \) and \( \angle T \) respectively. We will now apply the angle sum property of quadrilaterals:

\[ \angle Q + \angle R + \angle S + \angle T = 360^\circ \]

Substituting the known angles gives us:

\[ 108 + (108 - 2x) + \angle S + \angle T = 360 \]

Simplifying further:

\[ 216 - 2x + \angle S + \angle T = 360 \]

Rearranging the equation provides:

\[ \angle S + \angle T = 360 - 216 + 2x \] \[ \angle S + \angle T = 144 + 2x \]

Now, for QRST to be a parallelogram, the angles opposite each other must be equal, so we consider the angles Q and S, and R and T.

Let's say \( \angle S \) is equal to \( \angle Q \) and \( \angle T \) is equal to \( \angle R \):

If \( \angle S = \angle Q = 108^\circ \) (so its opposite angle is equal), then

\[ \angle T = (108 - 2x). \]

Since \( \angle T \) also equals \( R \):

\[ \angle T = 108 - 2x. \]

Setting these equal gives us:

\[ \angle T + \angle R = 180^\circ \quad \text{(since they should be supplementary)} \]

Thus,

\[ 108 + (108 - 2x) = 180 \] \[ 216 - 2x = 180 \] \[ -2x = 180 - 216 \] \[ -2x = -36 \] \[ x = 18. \]

Thus, we have found \( x = 18 \).

Now we assess our options considering Q and S as opposite angles:

Since QRST has opposite angles equal, we can conclude that quadrilateral QRST is indeed a parallelogram.

The correct response is:

"Quadrilateral QRST is a parallelogram because there are two pairs of parallel lines. The value \( x = 18 \) because the angles are supplementary."