Since ICRX can be mapped onto ZVAK by a translation, the corresponding angles are congruent. Therefore, m∠I = m∠Z, m∠C = m∠V, m∠R = m∠A, and m∠X = m∠K.
We are given that m∠X = 25°, so m∠K = 25°.
Quadrilateral
I
C
R
X
ICRX can be mapped onto quadrilateral
Z
V
A
K
ZVAK by a translation. If
m
∠
X
=
2
5
∘
m∠X=25
∘
, find
m
∠
K
m∠K.
1 answer