Quadrilateral ABCD

is inscribed in circle O
. The m∠B=4y+27
and m∠D=y−12
. Determine the m∠D
.(1 point)
m∠D=
°

1 answer

In a cyclic quadrilateral (a quadrilateral inscribed in a circle), the opposite angles are supplementary. This means that the sum of angles \( \angle B \) and \( \angle D \) is \( 180^\circ \).

Given: \[ m\angle B = 4y + 27 \] \[ m\angle D = y - 12 \]

According to the property of cyclic quadrilaterals: \[ m\angle B + m\angle D = 180^\circ \]

Substituting the expressions for \( m\angle B \) and \( m\angle D \) into this equation, we get: \[ (4y + 27) + (y - 12) = 180 \]

Now, simplify the equation: \[ 4y + 27 + y - 12 = 180 \] \[ 5y + 15 = 180 \]

Next, isolate \( y \) by subtracting 15 from both sides: \[ 5y = 180 - 15 \] \[ 5y = 165 \]

Now, divide both sides by 5: \[ y = \frac{165}{5} = 33 \]

Now that we have the value of \( y \), we can find \( m\angle D \): \[ m\angle D = y - 12 = 33 - 12 = 21 \]

Thus, the measure of angle \( D \) is: \[ \boxed{21^\circ} \]