Since quadrilaterals ABCD, LMNO, and STUV are congruent, their corresponding sides and diagonals are equal in length. Given that STUV is a rectangle and has diagonals SU that measure 5 cm, we know that in a rectangle, the diagonals are equal in length.
Thus, diagonals SV in rectangle STUV are also equal to 5 cm. Because all three quadrilaterals are congruent, the lengths of the diagonals AC and BD in quadrilateral ABCD (which is congruent to STUV) must be the same as the diagonals in STUV.
Therefore, according to the transitive property of equality:
AC = 5 cm
BD = 5 cm
So the lengths of diagonals AC and BD are 5 cm.
Hence, AC and BD = 5 cm.
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