To find the vertex of the quadratic function \( h = 6t^2 - 24t + 30 \), we can use the vertex formula for a quadratic in the form \( ax^2 + bx + c \). The \( t \)-coordinate of the vertex is given by:
\[ t = -\frac{b}{2a} \]
Here, \( a = 6 \) and \( b = -24 \).
Calculating the \( t \)-coordinate of the vertex:
\[ t = -\frac{-24}{2 \cdot 6} = \frac{24}{12} = 2 \]
Next, we need to find the \( h \)-coordinate by substituting \( t = 2 \) back into the equation:
\[ h = 6(2)^2 - 24(2) + 30 \] \[ h = 6(4) - 48 + 30 \] \[ h = 24 - 48 + 30 \] \[ h = 6 \]
Thus, the vertex is at the point \( (2, 6) \).
So the best interpretation of the vertex in this context is:
\[ \boxed{(2, 6)} \]
This point indicates that at \( t = 2 \) seconds, the owl reaches its maximum height of \( 6 \) feet above the ground.