To solve the quadratic equation \( 49x^2 + 392x + 784 = 0 \) using the perfect square trinomial pattern, we first rewrite it in standard form.
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Rewrite the equation: \[ 49x^2 + 392x + 784 = 0 \]
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Factor out the common factor (49) from the left side: \[ 49(x^2 + 8x + 16) = 0 \] \[ 49(x + 4)^2 = 0 \]
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Set the squared term equal to zero: \[ (x + 4)^2 = 0 \]
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Solve for \( x \): \[ x + 4 = 0 \] \[ x = -4 \]
So, the correct solution is: x = -4.