To solve the quadratic equation \((x + 12)^2 = 9\) using square roots, we can follow these steps:
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Take the square root of both sides. Remember to consider both the positive and negative square roots: \[ x + 12 = 3 \quad \text{or} \quad x + 12 = -3 \]
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Solve each equation for \(x\):
For the first equation: \[ x + 12 = 3 \] \[ x = 3 - 12 \] \[ x = -9 \]
For the second equation: \[ x + 12 = -3 \] \[ x = -3 - 12 \] \[ x = -15 \]
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Therefore, the solutions are: \[ x = -9 \quad \text{and} \quad x = -15 \]
Thus, the answer is \({-9, -15}\).
Response: {−9,−15} (left brace negative 9 comma negative 15 right brace)