Quadratic equation whose roots are 5 and -5 with coefficient 3
using the letter x to represent the variable
please show steps
3 answers
What did you get ?
3(x-5) (x+5)= 3x^2-28x + 75
Your expansion is incorrect
3(x-5)(x+5)
= 3(x^2 - 25)
= 3x^2 - 75
Since you wanted a quadratic equation, it should be
3x^2 - 75 = 0
3(x-5)(x+5)
= 3(x^2 - 25)
= 3x^2 - 75
Since you wanted a quadratic equation, it should be
3x^2 - 75 = 0