Qingyun has constructed a circle with center O

and chords AB
and CD
that intersect at point E
inside the circle. According to her measurements, segment a=13
mm, segment b=20
mm, and segment d=10
mm. What is the length of chord CD
?

(1 point)

1 answer

To find the length of chord CD in this situation, we can use the intersecting chords theorem. This theorem states that if two chords AB and CD intersect at point E inside a circle, then the products of the lengths of the segments of each chord are equal.

According to the information given:

  • Chord AB has segments AE = a = 13 mm and EB = b = 20 mm.
  • Chord CD has segments CE = c and ED = d = 10 mm.

Using the theorem, we can express the relationship as follows:

\[ AE \times EB = CE \times ED \]

Substituting the known values into this equation:

\[ 13 \times 20 = CE \times 10 \]

Calculating the left side:

\[ 260 = CE \times 10 \]

Now, we can find CE by isolating it:

\[ CE = \frac{260}{10} = 26 , \text{mm} \]

Now that we have both segments of chord CD (CE and ED), we can find the length of chord CD:

\[ CD = CE + ED = 26 , \text{mm} + 10 , \text{mm} = 36 , \text{mm} \]

Thus, the length of chord CD is \( \boxed{36} \) mm.

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