To find the length of chord CD in this situation, we can use the intersecting chords theorem. This theorem states that if two chords AB and CD intersect at point E inside a circle, then the products of the lengths of the segments of each chord are equal.
According to the information given:
- Chord AB has segments AE = a = 13 mm and EB = b = 20 mm.
- Chord CD has segments CE = c and ED = d = 10 mm.
Using the theorem, we can express the relationship as follows:
\[ AE \times EB = CE \times ED \]
Substituting the known values into this equation:
\[ 13 \times 20 = CE \times 10 \]
Calculating the left side:
\[ 260 = CE \times 10 \]
Now, we can find CE by isolating it:
\[ CE = \frac{260}{10} = 26 , \text{mm} \]
Now that we have both segments of chord CD (CE and ED), we can find the length of chord CD:
\[ CD = CE + ED = 26 , \text{mm} + 10 , \text{mm} = 36 , \text{mm} \]
Thus, the length of chord CD is \( \boxed{36} \) mm.