Q. The rondo stared 7 minutes late. It was scheduled to last 3 hours. But it ran 22 minutes longer. If the rodeo ended at 9:59 p.m, at what time did it begin?

Question

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A. So, do I mulpite 7 by 3 = 21, than muplite that answer by 22. than divide that by 9:59 p.m?

Answer 1

Well you can do something like this.
9:59
subtract 3 hours. which is 6:59
then you do the math with 22 min and 7 min. let me think about that hold on.

Answer 2

Since it started 7 min. late you can add 7 minutes to 6:59 which is 7:06.
then I'm not sure what to do with the 22 min.

Answer 3

Sorry this is the right way.. not the way I said it above.
I got it!!

9:59 - 22 (since it ran 22 min longer)
you get 9:37
now subtract 3 hours. you get 6:37
since it started 7 min late add 7 to 6:37, which equals 6:44
Then subtract 7 by 22
22- 7= 15. I did this because it started 7 min. late and ended 22 min longer. So you would want to subtract. i don't really know how to explain why I subtracted 7 and 22.. but It makes sense in my head..sorry.
since 22-7=15 add 15 to 6:44
6:44 + 15= 6:59.. now add those 3 hours and you get 9:59

Answer 4

Thank you!