Q:The ratio of the perimeters of two square is 5 to 4. If the area of the smaller square is 36 units, what is the area of the larger square?
A: 56.25
My teacher told us the answer, 56.25, so that we could correct it. But I don't understand how she got the answer at all, so can someone please help me solve the question so that I could understand how to do it.
4 answers
can someone please help me :0
a1 = the side length side of the smaller square
a2 = the side length side of the larger square
The area of the smaller square is 36
A1 = a1 ^ 2 = 36
a1 ^ 2 = 36
a1 = sqrt ( 36 ) = 6
Perimeter of square = 4 side length
In this case :
4 a2 / 4 a1 = 5 / 4
a2 / a1 = 5 / 4
a2 / 6 = 5 / 4 Multiply both sideas by 6
a2 = 5 * 6 / 4 = 30 / 4 = 15 / 2 = 7.5
The area of the larger square :
A2 = a2 ^ 2 = 7.5 ^ 2 = 56.25
a2 = the side length side of the larger square
The area of the smaller square is 36
A1 = a1 ^ 2 = 36
a1 ^ 2 = 36
a1 = sqrt ( 36 ) = 6
Perimeter of square = 4 side length
In this case :
4 a2 / 4 a1 = 5 / 4
a2 / a1 = 5 / 4
a2 / 6 = 5 / 4 Multiply both sideas by 6
a2 = 5 * 6 / 4 = 30 / 4 = 15 / 2 = 7.5
The area of the larger square :
A2 = a2 ^ 2 = 7.5 ^ 2 = 56.25
thank you :D
a1 = the length side of the smaller square
a2 = the length side of the larger square
a2 = the length side of the larger square
2 answers