Question

Q 2) A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal ?

Answer 1

Consider a simple haemonic motion of time period T . Calculate the time taken for the displacement to change value from half the amplitude to the amplitude.

Answer 2

KE is half of the total energy when the potential energy is also half the total. Since PE is proportional to displacement^2, the displacement would be sqrt(1/2) = 70.7% of the maximum value.

Answer 3

Please post followup questions separately