Mols of,
S=(96/32)mol =3 mol
C=(36/12)mol= 3 mol
2S + C --> CS2
(3-3) (3-1.5) (+1.5) mol
a)=(3/2)mol*78g/mol
b) 1.5 mols of Carbon
=(3/2)mol*12g/mol
Q#2..96g of sulphur reacts with 36g of carbon according to the following equation and produces carbon disulphide
2S + C = CS2
(a) the mass of carbon disulphide
(b) the excess amount of the reagent in grams that is left unreacted.
2 answers
what is the ph of 50ml buffer solution which is 2M in CH3COOH and 2M in CH3CooNa?
1 Initial PH before the addition of acids and base?
2 What is the new PH after 2ml of 6.00M HCl is added to this buffer?
3 what is the new PH after 2.00ml of 6.00M NaoH is added to the original buffer?
1 Initial PH before the addition of acids and base?
2 What is the new PH after 2ml of 6.00M HCl is added to this buffer?
3 what is the new PH after 2.00ml of 6.00M NaoH is added to the original buffer?
0 answers