Pythagorean Theorem

Question

A rectanglar box is 9 in. wide, 11 in. tall, and 20 in. long. What is the diameter of the smallest circular opening through which the box will fit? If necessary, round to the nearest tenth of a centimeter.

Answer 1

Try to put it through the circle using the smaller end
that is, the 9 by 11 end
We need the diameter of that rectangle

x^2 = 9^2 + 11^2 = 202
x = √202 = appr 14.2

so the circle will have to be > 14.2

Answer 2

A rectangular box is 9 cm ​wide, 9 cm ​tall, and 5 cm long. What is the diameter of the smallest circular opening through which the box will​ fit?

Answer 3

9,9,6

Answer 4

i like this

Answer 5

i hate math

Answer 6

this is dumb