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Put the simplified expressions in order on the number line from least to greatest. (-2)^-8*(-2)^11 (1/2)^-3 2^6-2^4/2^2 1/4^-2Asked by I
Put the simplified expressions in order on the number line from least to greatest.
(-2)^-8.(2)^11
(1/2)^3
2^6 -2^4/2^2
1/4^-2
(-2)^-8.(2)^11
(1/2)^3
2^6 -2^4/2^2
1/4^-2
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Answered by
GPT-4o mini
Let's simplify each expression step by step before ordering them.
1. **Expression 1:** \((-2)^{-8} \cdot (2)^{11}\)
\[
(-2)^{-8} = \frac{1}{(-2)^8} = \frac{1}{256}
\]
Since \((-2)^8 = (2^8) = 256\), we have:
\[
(-2)^{-8} \cdot (2)^{11} = \frac{1}{256} \cdot 2^{11} = \frac{2^{11}}{256}
\]
Now calculating \(2^{11} = 2048\):
\[
(-2)^{-8} \cdot (2)^{11} = \frac{2048}{256} = 8
\]
2. **Expression 2:** \((\frac{1}{2})^3\)
\[
(\frac{1}{2})^3 = \frac{1}{2^3} = \frac{1}{8}
\]
3. **Expression 3:** \(2^6 - \frac{2^4}{2^2}\)
\[
2^6 = 64 \quad \text{and} \quad \frac{2^4}{2^2} = 2^{4-2} = 2^2 = 4
\]
Thus,
\[
2^6 - \frac{2^4}{2^2} = 64 - 4 = 60
\]
4. **Expression 4:** \(\frac{1}{4^{-2}}\)
\[
4^{-2} = \frac{1}{4^2} = \frac{1}{16} \quad \text{so} \quad \frac{1}{4^{-2}} = \frac{1}{\frac{1}{16}} = 16
\]
Now we have the simplified values:
- Expression 1: \(8\)
- Expression 2: \(\frac{1}{8}\)
- Expression 3: \(60\)
- Expression 4: \(16\)
Now let's order these values from least to greatest:
\[
\frac{1}{8} < 8 < 16 < 60
\]
Putting it all together, the order from least to greatest is:
\[
(1/2)^3 < (-2)^{-8} \cdot (2)^{11} < 1/4^{-2} < 2^6 - \frac{2^4}{2^2}
\]
Thus, the final order of the expressions is:
1. \((\frac{1}{2})^3\)
2. \((-2)^{-8} \cdot (2)^{11}\)
3. \(\frac{1}{4^{-2}}\)
4. \(2^6 - \frac{2^4}{2^2}\)
1. **Expression 1:** \((-2)^{-8} \cdot (2)^{11}\)
\[
(-2)^{-8} = \frac{1}{(-2)^8} = \frac{1}{256}
\]
Since \((-2)^8 = (2^8) = 256\), we have:
\[
(-2)^{-8} \cdot (2)^{11} = \frac{1}{256} \cdot 2^{11} = \frac{2^{11}}{256}
\]
Now calculating \(2^{11} = 2048\):
\[
(-2)^{-8} \cdot (2)^{11} = \frac{2048}{256} = 8
\]
2. **Expression 2:** \((\frac{1}{2})^3\)
\[
(\frac{1}{2})^3 = \frac{1}{2^3} = \frac{1}{8}
\]
3. **Expression 3:** \(2^6 - \frac{2^4}{2^2}\)
\[
2^6 = 64 \quad \text{and} \quad \frac{2^4}{2^2} = 2^{4-2} = 2^2 = 4
\]
Thus,
\[
2^6 - \frac{2^4}{2^2} = 64 - 4 = 60
\]
4. **Expression 4:** \(\frac{1}{4^{-2}}\)
\[
4^{-2} = \frac{1}{4^2} = \frac{1}{16} \quad \text{so} \quad \frac{1}{4^{-2}} = \frac{1}{\frac{1}{16}} = 16
\]
Now we have the simplified values:
- Expression 1: \(8\)
- Expression 2: \(\frac{1}{8}\)
- Expression 3: \(60\)
- Expression 4: \(16\)
Now let's order these values from least to greatest:
\[
\frac{1}{8} < 8 < 16 < 60
\]
Putting it all together, the order from least to greatest is:
\[
(1/2)^3 < (-2)^{-8} \cdot (2)^{11} < 1/4^{-2} < 2^6 - \frac{2^4}{2^2}
\]
Thus, the final order of the expressions is:
1. \((\frac{1}{2})^3\)
2. \((-2)^{-8} \cdot (2)^{11}\)
3. \(\frac{1}{4^{-2}}\)
4. \(2^6 - \frac{2^4}{2^2}\)
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