PE=1/2 kx^2
.0020=1/2 k (.055^2)
solve for k
b. PE is directly proportional to the saqaure of compression, so
.0079/.0020 = (x/.55cm)^2
x in cm= .55cm * sqrt(.0079/.0020 )
Pushing on the pump of a soap dispenser compresses a small spring. When the spring is compressed 0.55 cm , its potential energy is 0.0020 J
a.What is the force constant of the spring? i found the fist answer is 130N/M
B. What compression is required for the spring potential energy to equal 0.0079 J ? pls help part with b
1 answer
0 answers