Pure helium is closed into cylinder with a movable piston. The initial volume, pressure, and temperature of the gas are 15 dm3, 2·105 Pa, and 300 K, respectively. If volume is decreased to 12 dm3 and the pressure increase to 3.5·105 Pa find the final temperature of the gas.

Question

Pure helium is closed into  cylinder with a movable piston.  The initial volume, pressure, and temperature of the gas are 15 dm3, 2·105 Pa, and 300 K, respectively. If volume is decreased to 12 dm3 and the pressure increase to 3.5·105 Pa find the final temperature of the gas.

Damon · Answer

P V/T = n R n and R are the same for both P1 V1/T1 = P2 V2/T2 P1 V1 T2 = P2 V2 T1 T2 = T1 (P2/P1)(V2/V1) luckily using degrees Kelvin so T2 = 300 (3.5/2)(12/15)