If I get past the font gibberish, I sense that you want to prove that
4 sinθ sin(60-θ) sin(60θ) = sin 3θ
That isn't so, so try reposting using
sin^3 θ for cube of sinθ if that's what you mean.
provide that 4sin¦Ðsin(60¡ã-¦Ð)sin(60 ¦Ð)=sin3¦Ð
2 answers
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