There is more than one use of the Grignard reaction to prepare each of these. In practice you would consider cost of starting materials and ease of separation of the product(s) from starting materials.
I assume we are going to use the original Mg based version rather than any of the variations.
A)
CH3CH2Br + Mg -> CH3CH2MgBr
CH3CH3MgBr+CH3CH3CHO ->CH3CH2CH(OH)CH2CH3
B) CH3CH2CH2CH2CH2Br + Mg -> CH3CH2CH2CH2CH2MgBr
CH3CH2CH2CH2CH2MgBr + CO2 -> CH3CH2CH2CH2CH2CH2H
C)CH3CH2C(CH3)(OH)CH2CH3
2-hydroxy-2-methylpentane
CH3Br + Mg -> CH3MgBr
CH3MgBR + CH3CH2C(=O)CH2CH3 -> CH3CH2C(CH3)(OH)CH2CH3
D)Ph=benzene ring
PhCHOHCH2CH3
PhBr + Mg ->PhMgBr
PhMgBr + CH3CH2CHO -> PhCH(OH)CH2CH3
There are alternative answers to each of these, for example for D)
PhCHO (benzaldehyde) + CH3CH2MgBr -> PhCH(OH)CH2CH3
Provide methods for preparing the following compounds by the Grignard method:
A) 3-pentanol
B) Hexanoic acid
There are also 2 more, but I don't even know how to name them.
C) CH3CH2CCH3OHCH2CH3
D) A cycloalkene (3 double bonds-alternated) with CHOHCH2CH3 attached to it
Please help... I am really lost in this class.
5 answers
oops just spotted a typo in B)
the last line should be
CH3CH2CH2CH2CH2MgBr + CO2 -> CH3CH2CH2CH2CH2CO2H
You might like to have a closer look at D) and decide which of the two methods might be preferred and why. Things to consider are the possible by-products and unused starting materials.
the last line should be
CH3CH2CH2CH2CH2MgBr + CO2 -> CH3CH2CH2CH2CH2CO2H
You might like to have a closer look at D) and decide which of the two methods might be preferred and why. Things to consider are the possible by-products and unused starting materials.
Thank you so much. However, I thought B) hexanoic acid had to have a C=OOH?
Oops, I didn't get the correction note before I submitted, but thanks I appreciate your help.
CH3CH2C(=O)CH2CH3