1st one:
y = k(1/x^4)
when x=2, y=3
3 = k(1/16) ---> k = 48
equation: y = 48/x^4
when y = .5
.5 = 48/x^4
x^4 = 96
y = 96^(1/4) = 2(6^(1/4) or appr. 3.13
you try the second one, using the same method
Start with
Q = k/√R
Provide an appropraite response.
If y varies inversly as the 4th power of x and y=3 when x=2, what is y when x=0.5?
If Q varies inversly as the sqaure root of R and Q=2 whe R=4, what is Q when R is 25?
2 answers
is the second one R=625?
0 answers