Prove the following trigonometric identities

1. tanx = sinx + sin^2x/cosx(1+sinx)

2. cos^3+(cosx)(sin^2x) = 1/secx

1 answer

1. The way you typed it, the identity is false, but I am sure you meant

tanx = (sinx + sin^2x)/(cosx(1 + sinx))

RS = sinx(1 + sinx) / (cosx(1+sinx))
= sinx/cosx
= tanx
= LS

2. LS = cosx(cos^2x + sin^2x)
= (cosx)(1)
= cosx
RS = 1/secx
= cosx
= LS
Similar Questions
  1. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
  2. Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
    1. answers icon 1 answer
  3. How do I prove these trig identities?secx-cosx/tanx =sinx And 1+sinx/cosx+ cox/ 1+sinx=2secx
    1. answers icon 1 answer
  4. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
more similar questions