To prove that quadrilateral ABCD is a parallelogram given that ∠A ≅ ∠C and ∠B ≅ ∠D, we can follow these steps:
Statements | Reasons
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1. ∠A ≅ ∠C and ∠B ≅ ∠D | Given
2. m∠A + m∠B + m∠C + m∠D = 360° | Sum of interior angles of a quadrilateral
3. m∠A + m∠B + m∠A + m∠B = 360° | Substitute ∠C with ∠A and ∠D with ∠B (from statement 1)
4. 2m∠A + 2m∠B = 360° | Combine like terms
5. m∠A + m∠B = 180° | Divide both sides by 2
6. ∠A + ∠B = 180° and ∠C + ∠D = 180° | ∠C = ∠A and ∠D = ∠B (from statement 1)
7. ABCD is a parallelogram | If two pairs of opposite angles are supplementary, then the quadrilateral is a parallelogram
Matching Responses:
a. ∠A ≅ ∠C and ∠B ≅ ∠D
b. m∠A + m∠B + m∠C + m∠D = 360°
c. m∠A + m∠B + m∠A + m∠B = 360°
d. 2m∠A + 2m∠B = 360°
e. m∠A + m∠B = 180°
f. ∠A + ∠B = 180° and ∠C + ∠D = 180°
g. ABCD is a parallelogram
This proof shows that if both pairs of opposite angles of a quadrilateral are congruent, then the angles sum to 180 degrees in pairs, which establishes that the quadrilateral is a parallelogram.