A+AB = A(1+B) = A(1) = A
(A+B)(A+C) = A(A+C)+B(A+C) = A+AB+BC = A+BC
prove the following rules if true or false using Boolean algebra
(a)A+AB = A+B
(b)(A+B)(A+C) = A+BC
1 answer
(a)A+AB = A+B
(b)(A+B)(A+C) = A+BC
1 answer