Prove the following identity:-

(i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx

1 answer

You obviously did not read my reply to that same question, since you did not change the typing using brackets.

I still cannot tell who is divided by who ....

http://www.jiskha.com/display.cgi?id=1307704739
Similar Questions
  1. Prove:sin2x / 1 - cos2x = cotx My Attempt: LS: = 2sinxcosx / - 1 - (1 - 2sin^2x) = 2sinxcosx / - 1 + 2sin^2x = cosx / sinx - 1 =
    1. answers icon 5 answers
  2. (sinx - cosx)(sinx + cosx) = 2sin^2x -1I need some tips on trigonometric identities. Why shouldn't I just turn (sinx + cosx)
    1. answers icon 2 answers
  3. 1. Prove the identity:cosx/1-tanx+sinx/1-cotx=sinx+cosx2.Prove the identity: cosx/1+sinx+1+sinx/cosx=2secx
    1. answers icon 0 answers
  4. prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
    1. answers icon 0 answers
more similar questions