prove that x^0=1
answered below.
Look under the question by lee just a few problems below.
Since a^m x a^n = a^(m+n) for all values of m and n, by replacing the exponent m by 0, we get
a^0 x a^n = a^(0 + n) = a^n
Then, a^0 = a^n/a^n = 1.
Therefore, any quantity with a zero exponent is equal to 1.