prove that x^0=1

Question

answered below.

Look under the question by lee just a few problems below.

Since a^m x a^n = a^(m+n) for all values of m and n, by replacing the exponent m by 0, we get

a^0 x a^n = a^(0 + n) = a^n

Then, a^0 = a^n/a^n = 1.

Therefore, any quantity with a zero exponent is equal to 1.