To prove that the product of the two rational numbers \( \sqrt{36} \) and \( \frac{5}{3} \) is a rational number, we first calculate the product.
We know: \[ \sqrt{36} = 6 \] So, the product is: \[ 6 \times \frac{5}{3} = \frac{6 \times 5}{3} = \frac{30}{3} = 10 \]
Now, since both \( 6 \) and \( \frac{5}{3} \) are rational numbers (because \( 6 \) can be expressed as \( \frac{6}{1} \) and \( \frac{5}{3} \) is already in rational form), their product is also a rational number. In general, the product of any two rational numbers is rational because the product of two fractions (or integers) results in another fraction (or integer).
Thus, the product \( 10 \) is a rational number.