To prove that the product of \(\sqrt{36}\) and \(\frac{5}{3}\) is a rational number, we first calculate the product:
\[ \sqrt{36} = 6 \]
Now, we find the product:
\[ 6 \times \frac{5}{3} = \frac{6 \times 5}{3} = \frac{30}{3} = 10 \]
Since 10 is an integer, it is also a rational number (a rational number is any number that can be expressed as the quotient of two integers, where the denominator is not zero). Thus, the product of \(\sqrt{36}\) and \(\frac{5}{3}\) is rational.