To prove that the product of 2 and an irrational number is irrational, let's take an irrational number, like the square root of 2 (√2). If we multiply 2 by √2, we get 2√2.
Now, we need to show that 2√2 is irrational. If we assume that 2√2 is rational, this would mean that it can be expressed as a fraction of two integers (a/b). However, if we divide both sides of the equation by 2, we would have √2 = (a/b) / 2 = a/(2b), which implies that √2 is rational. But we know that √2 is irrational. Therefore, our initial assumption must be false, so 2√2 is irrational.
Thus, the product of 2 and an irrational number (like √2) results in another irrational number, which is 2√2.