Prove that tan4x=(4tanx-tan^3x)/(1-6tan^2 x+tan^4 x)
*note: the exponents are just numbers. there are no variables in the exponents.
2 answers
ukgggg
we know tan2A= 2tanA / 1-tan2A
using this formula,
tan4x = tan2.(2x)
=2tan2x / 1-tan22x
= 2(2tanx/1-tan2x) / 1-(2tanx/{1-tan2x}2)
simplify to get. , 4tanx(1-tan2x) / 1-6tan2x+tan4x.
using this formula,
tan4x = tan2.(2x)
=2tan2x / 1-tan22x
= 2(2tanx/1-tan2x) / 1-(2tanx/{1-tan2x}2)
simplify to get. , 4tanx(1-tan2x) / 1-6tan2x+tan4x.
1 answer