Prove that. √seca+2sina/seca-2sina=Sina+cosa/sina-cosa

Answer 1

I assume you mean

√((seca + 2sina)/(seca-2sina)) = (sina+cosa)/(sina-cosa)

well, clearly, the first thing to do is square both sides:

(seca + 2sina)/(seca-2sina)
= [(1+2sina*cosa)/cosa] / [(1-2sina*cosa)/cosa]
= (1+sin2a)/(1-sin2a)

see where that takes you, after squaring the right side.

Answer 2

3/2
=