LS = Log384/5+log81/32+3log5/3-log9
= Log384/5+log81/32+log5^3/3^3-log9
= log( (384/5)(81/32)(125/27)/9 )
= log(100)
= 2
= RS
Prove that
Log384/5+log81/32+3log5/3-log9= 2.
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