since
log_u(x)/log_v(x) = log_v(u) and
log_u(x) = 1/log_x(u), we have
log_a/b(a) = 1/log_a(a/b)
= log_a(a) + log_a(1/b)
= 1 + log_a(1/b)
If those two properties of logs have not yet been delivered to you, work to convince yourself that they are true. I'm sure you can find many proofs online.
Prove that log base a of x divided by log base a/b of x is equal to 1+log base a of(1/b)
Where do I start?
1 answer
1 answer