Prove that cot x + tan x = csc x * sec x whenever both sides are defined.

Question

I tried rewriting all sides in terms of sin x but it got all complicated and I can't make head or tail of it. Could someone assist me? Is it all just a pound-out algebra problem in essence? How do you simplfy sin x * sin x?

Answer 1

cot + tan
1/tan + tan
(1+tan^2)/tan
sec^2/tan
1/cos^2 * cos/sin
1/(sin*cos)
sec*csc

Answer 2

Thanks a lot!!!