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Prove that a function f : A -> B is one to one if and only if any non-empty subset S ⊆ A, f^-1 (f(S)) = S. DO NOT assume a priori that the inverse function f^-1 exists; in this question f^-1 (S) denotes the pre-image of S.
5 years ago

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Prove that a function f : A -> B is one to one if and only if any non-empty subset S ⊆ A, f^-1 (f(S)) = S. DO NOT assume a priori that the inverse function f^-1 exists; in this question f^-1 (S) denotes the pre-image of S.

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