To prove that 2cosx / (cos2x + 1) = secx, we first need to simplify the left side of the equation.
We know that cos 2x = 2(cosx)^2 - 1. So, we substitute cos 2x with 2(cosx)^2 - 1 in the original equation.
2cosx / (2(cosx)^2 - 1 + 1)
= 2cosx / 2(cosx)^2
Now, we simplify further by dividing the numerator and denominator by 2cosx.
= 1 / cosx
= secx
Therefore, 2cosx / (cos2x + 1) is indeed equal to secx.
Prove that 2cosx/cos2x+1=secx
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