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Prove:sin ^2(7π/8)+sin^2(5π/8)+sin^2(3π/8)+sin^2(π/8)=0
2 answers
Since sin(π-x) = sin(x),
sin 7π/8 = sin π/8
sin 5π/8 = sin 3π/8
But your equation is clearly false, since all those sin^2 are positive, so they cannot add to zero.
sin 7π/8 = sin π/8
sin 5π/8 = sin 3π/8
But your equation is clearly false, since all those sin^2 are positive, so they cannot add to zero.