To prove whether polygons ABCDEF and A'B'C'D'E'F' are congruent or not congruent, we need to show that the corresponding sides are equal in length and the corresponding angles are equal in measure.
Let's compare the corresponding sides of the two polygons:
1. Side AB (length √29) corresponds to side A'B' (length √29).
2. Side BC (length 4) corresponds to side B'C' (length 5).
3. Side CD (length 5) corresponds to side C'D' (length 5).
4. Side DE (length 5) corresponds to side D'E' (length 5).
5. Side EF (length √10) corresponds to side E'F' (length √10).
6. Side FA (length √26) corresponds to side F'A' (length √26).
Since all corresponding sides are equal in length, we can conclude that the polygons ABCDEF and A'B'C'D'E'F' are congruent.
Prove polygon ABCDEF and polygon A′B′C′D′E′F′ are congruent or not congruent.
Two polygons are graphed on a four quadrant coordinate plane. The x-axis and the y-axis go from negative 10 to 10 in increments of 1. The first polygon has vertices labeled A at left parenthesis negative 3 comma 1 right parenthesis, B at left parenthesis negative 7 comma 3 right parenthesis, C at left parenthesis negative 4 comma 3 right parenthesis, D at left parenthesis negative 3 comma 8 right parenthesis, E at left parenthesis negative 2 comma 3 right parenthesis, and F at left parenthesis 1 comma 3 right parenthesis. The second polygon has vertices labeled A prime at left parenthesis 5 comma 0 right parenthesis, B prime at left parenthesis 3 comma negative 4 right parenthesis, C prime at left parenthesis 3 comma negative 1 right parenthesis, D prime at left parenthesis negative 2 comma 0 right parenthesis, E prime at left parenthesis 3 comma 1 right parenthesis, and F prime at left parenthesis 3 comma 4 right parenthesis.
(2 points)
1 answer