Prove By induction that sinx + sin3x + sin5x +.... Sin(2n-1) =sin^2(nx)/sin3x

Question

Prove By induction that                      sinx + sin3x + sin5x +.... Sin(2n-1) =sin^2(nx)/sin3x

Rishabh · Accepted Answer

In the denominator it should be sinx

Steve · Answer

do as with all inductions. show that it's true for n=1 sinx = sin^2(x)/sin3x Nope, not true. So, how about n=2? sinx+sin3x = sin^2(2x)/sin3x Nope. Better fix this and come back.