prove as an identity
1/1+sin(x) + 1/1-sin(x)
3 answers
oops i forgot the =2sec^2
identities are equations.
I don't see an equation.
I don't see an equation.
so it is 1/(1+sinx) + 1/(1-sinx) = 2sec^2 x
LS
= (1 - sinx + 1 + sinx)/((1+sinx)(1-sinx))
= 2/(1 - sin^2x)
= 2 cos^2x
= 2sec^2x
= RS
LS
= (1 - sinx + 1 + sinx)/((1+sinx)(1-sinx))
= 2/(1 - sin^2x)
= 2 cos^2x
= 2sec^2x
= RS