How about some parentheses, so we can tell what's what?
As it stands, it means
1 + tan2A = cosA + tanA - sinA
which is clearly false
Prove :
1 + Sin2A/ Cos2A = CosA + SinA / CosA- SinA
5 answers
Clive probably meant:
(1+sin 2A)/cos 2A = (cosA + sinA)/(cosA - sinA)
LS = (sin^2 A + cos^2 A + 2sinAcosA)/(cos^2 A - sin^2 A)
= (cosA + sinA)/( difference of squares)
= ...
I am sure you can take it from there
(1+sin 2A)/cos 2A = (cosA + sinA)/(cosA - sinA)
LS = (sin^2 A + cos^2 A + 2sinAcosA)/(cos^2 A - sin^2 A)
= (cosA + sinA)/( difference of squares)
= ...
I am sure you can take it from there
I AM WRONG >
if x = rsinAcosC,y=rsinA sinC and z = rcosA,then prove that r2= x2+y2+z2
There is no solution for 1
1 answer