At 600.
Take 100 mols as an arbitrary number.
.......CH3CH3CH3 ==> CH3CH=CH2 + H2
I.......100............0..........0
C........-x............x..........x
E......100-x...........x..........x
Ka = 0.104 = (x)(x)/(100-x)
Solve for x for mols = x, then
(x/100) = fraction converted.
I estimate about 14% but check me out on that.
Propylene can be produced from the dehydrogenation of propane over a catalyst.
At atmospheric pressure, what is the fraction of propane converted to propylene at 400, 500, and 600°C if equilibrium is reached at each temperature? Assume ideal behavior.
(Temperature(C)
400 ka:0.000521
500 ka:0.0104
600 ka:0.104
1 answer