The balanced equation shows that 2 moles of propene produce 6 moles of carbon dioxide. Therefore, for 100 g of propene, the theoretical yield of carbon dioxide would be:
(100 g propene) / (42 g/mol propene) x (6 mol CO2 / 2 mol propene) x (44 g/mol CO2) = 378.1 g CO2
The percent yield can now be calculated by dividing the actual yield (200 g) by the theoretical yield (378.1 g) and multiplying by 100:
Percent yield = (200 g / 378.1 g) x 100% = 52.9%
Therefore, the correct answer is not provided as an option.
Propene, C3H6 (100 g) was subjected to combustion. The actual yield of carbon dioxide is 200 g. Calculate the percent yield of carbon dioxide.
2 C3H6 + 9 O2 → 6 H2O+ 6 CO2
(Molar mass: C=12 g/mol; H= 1g/mol; O =16 g/mol)
64.00%
45.45%
22.80%
22.75%
1 answer