pH = pKa + log (base)/(acid)
5.25 = pKa + log (base)/(M x L)
Solve for base and since the acid is in mols, the base will be in mols.
Then mols = grams/molar mass. You know molar mass and mols, solve for grams. That will be the number of grams of the salt to add to the 532.9 mL of the acid.
Propanoic acid that, along with its sodium salt, can be used to make a buffer that has a pH of 5.25. If you have 532.9 mL of a 0.250 M solution of that acid, how many grams of the corresponding sodium salt do you have to dissolve to obtain the desired pH?
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