Problem: Given any 3 non-collinear points, find the equation of the circle that contains them.

1. You need to select 3 non-collinear points, to use in the solution. The first point will be in quadrant 1, so choose a point with x and y coordinates between 5 and 25 first point:(___,___)

2. Let the 2nd point be in quadrant 2, again with values between 5 and 25, or -5 and -25, but select different values than you did for the first point
second point: (____,____)

3. Your 3rd point can be in quadrant 3 or 4. use the range of values as above, but again make sure the values are different from the first two points.
third point: (____,____)
4. Create a scatter plot

5. Location of mid-point between first and second point
x=_______ y=______
6. Location of mid-point between second and third point
x=_______ y=______

7.Equation of the perpendicular bisector of the line segment between the first and second point.
Y=_______

8.Equation of the perpendicular bisector of the line segment between the second and third point.
Y=_______

9. Center (___,___) rounded to 0.001

10. radius of the circle (rounded to 0.001)
r=_______

11. Equation of the circle
__________________

1 answer

what, you don't know how to do any of those steps?
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