Problem:
An excited hydrogen atom could, in principle, have a radius of 2.50 mm .
________
Part A:
What would be the value of n for a Bohr orbit of this size?
Answer--> n= 6.87×103
_______
Part B
What would its energy be?
Answer--> E=_______eV
[Note: I got 4.61x10^-26 for part B but I got it wrong 3 times. Please help]
2 answers
Part A answer is n= 6.87x10^3
Rn = n^2 * R1
2.50E-3 m = n^2 * .53E-10 m
En = (13.6 / n^2) eV
2.50E-3 m = n^2 * .53E-10 m
En = (13.6 / n^2) eV
2 answers