Problem:

$AB$ and $AC$ are equal legs in $\triangle ABC$. Point $D$ lies on $AB$ such that $CD = CB$. If $\angle ADC = 114^\circ$, what is $\angle ACD$ in degrees?

1 answer

BDC = 66
so, DBC = 66
BCD = 48
ACB=66, so ACD = 18
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