BDC = 66
so, DBC = 66
BCD = 48
ACB=66, so ACD = 18
Problem:
$AB$ and $AC$ are equal legs in $\triangle ABC$. Point $D$ lies on $AB$ such that $CD = CB$. If $\angle ADC = 114^\circ$, what is $\angle ACD$ in degrees?
1 answer